(5n+7)(n-1)=0

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Solution for (5n+7)(n-1)=0 equation:



(5n+7)(n-1)=0
We multiply parentheses ..
(+5n^2-5n+7n-7)=0
We get rid of parentheses
5n^2-5n+7n-7=0
We add all the numbers together, and all the variables
5n^2+2n-7=0
a = 5; b = 2; c = -7;
Δ = b2-4ac
Δ = 22-4·5·(-7)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-12}{2*5}=\frac{-14}{10} =-1+2/5 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+12}{2*5}=\frac{10}{10} =1 $

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