3(x+1)(x-1)=3(x+1)(x-2)+9

Solution for 3(x+1)(x-1)=3(x+1)(x-2)+9 equation:

3(x+1)(x-1)=3(x+1)(x-2)+9

We move all terms to the left:

3(x+1)(x-1)-(3(x+1)(x-2)+9)=0

We use the square of the difference formula

x^2-(3(x+1)(x-2)+9)-1=0

We multiply parentheses ..

x^2-(3(+x^2-2x+x-2)+9)-1=0


We calculate terms in parentheses: -(3(+x^2-2x+x-2)+9), so:

3(+x^2-2x+x-2)+9

We multiply parentheses

3x^2-6x+3x-6+9

We add all the numbers together, and all the variables

3x^2-3x+3

Back to the equation:

-(3x^2-3x+3)


We get rid of parentheses

x^2-3x^2+3x-3-1=0

We add all the numbers together, and all the variables

-2x^2+3x-4=0

a = -2; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-2)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation