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3x^2+4x-832=0
a = 3; b = 4; c = -832;
Δ = b2-4ac
Δ = 42-4·3·(-832)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-100}{2*3}=\frac{-104}{6} =-17+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+100}{2*3}=\frac{96}{6} =16 $
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