3(w+5)=6(w+5)-2w

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Solution for 3(w+5)=6(w+5)-2w equation: 



3(w+5)=6(w+5)-2w

We move all terms to the left:

3(w+5)-(6(w+5)-2w)=0

We multiply parentheses

3w-(6(w+5)-2w)+15=0



We calculate terms in parentheses: -(6(w+5)-2w), so:

6(w+5)-2w

We add all the numbers together, and all the variables

-2w+6(w+5)

We multiply parentheses

-2w+6w+30

We add all the numbers together, and all the variables

4w+30

Back to the equation:

-(4w+30)



We get rid of parentheses

3w-4w-30+15=0

We add all the numbers together, and all the variables

-1w-15=0

We move all terms containing w to the left, all other terms to the right

-w=15

w=15/-1

w=-15

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