3x-5(2-x)=7(x+1)-(1-x)

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Solution for 3x-5(2-x)=7(x+1)-(1-x) equation: 



3x-5(2-x)=7(x+1)-(1-x)

We move all terms to the left:

3x-5(2-x)-(7(x+1)-(1-x))=0

We add all the numbers together, and all the variables

3x-5(-1x+2)-(7(x+1)-(-1x+1))=0

We multiply parentheses

3x+5x-(7(x+1)-(-1x+1))-10=0



We calculate terms in parentheses: -(7(x+1)-(-1x+1)), so:

7(x+1)-(-1x+1)

We multiply parentheses

7x-(-1x+1)+7

We get rid of parentheses

7x+1x-1+7

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

8x-(8x+6)-10=0

We get rid of parentheses

8x-8x-6-10=0

We add all the numbers together, and all the variables

-16!=0

There is no solution for this equation

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