3(w+2)+4=4(w-1)+9

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Solution for 3(w+2)+4=4(w-1)+9 equation: 



3(w+2)+4=4(w-1)+9

We move all terms to the left:

3(w+2)+4-(4(w-1)+9)=0

We multiply parentheses

3w-(4(w-1)+9)+6+4=0



We calculate terms in parentheses: -(4(w-1)+9), so:

4(w-1)+9

We multiply parentheses

4w-4+9

We add all the numbers together, and all the variables

4w+5

Back to the equation:

-(4w+5)



We add all the numbers together, and all the variables

3w-(4w+5)+10=0

We get rid of parentheses

3w-4w-5+10=0

We add all the numbers together, and all the variables

-1w+5=0

We move all terms containing w to the left, all other terms to the right

-w=-5

w=-5/-1

w=+5

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