-4+15-x=2(6-2x)-x

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Solution for -4+15-x=2(6-2x)-x equation: 



-4+15-x=2(6-2x)-x

We move all terms to the left:

-4+15-x-(2(6-2x)-x)=0

We add all the numbers together, and all the variables

-x-(2(-2x+6)-x)-4+15=0

We add all the numbers together, and all the variables

-1x-(2(-2x+6)-x)+11=0



We calculate terms in parentheses: -(2(-2x+6)-x), so:

2(-2x+6)-x

We add all the numbers together, and all the variables

-1x+2(-2x+6)

We multiply parentheses

-1x-4x+12

We add all the numbers together, and all the variables

-5x+12

Back to the equation:

-(-5x+12)



We get rid of parentheses

-1x+5x-12+11=0

We add all the numbers together, and all the variables

4x-1=0

We move all terms containing x to the left, all other terms to the right

4x=1

x=1/4

x=1/4

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