3(w+2)+2=7(w-1)+9

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Solution for 3(w+2)+2=7(w-1)+9 equation: 



3(w+2)+2=7(w-1)+9

We move all terms to the left:

3(w+2)+2-(7(w-1)+9)=0

We multiply parentheses

3w-(7(w-1)+9)+6+2=0



We calculate terms in parentheses: -(7(w-1)+9), so:

7(w-1)+9

We multiply parentheses

7w-7+9

We add all the numbers together, and all the variables

7w+2

Back to the equation:

-(7w+2)



We add all the numbers together, and all the variables

3w-(7w+2)+8=0

We get rid of parentheses

3w-7w-2+8=0

We add all the numbers together, and all the variables

-4w+6=0

We move all terms containing w to the left, all other terms to the right

-4w=-6

w=-6/-4

w=1+1/2

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