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x(x+1)+(x+2)(x+3)=-42
We move all terms to the left:
x(x+1)+(x+2)(x+3)-(-42)=0
We add all the numbers together, and all the variables
x(x+1)+(x+2)(x+3)+42=0
We multiply parentheses
x^2+x+(x+2)(x+3)+42=0
We multiply parentheses ..
x^2+(+x^2+3x+2x+6)+x+42=0
We get rid of parentheses
x^2+x^2+3x+2x+x+6+42=0
We add all the numbers together, and all the variables
2x^2+6x+48=0
a = 2; b = 6; c = +48;
Δ = b2-4ac
Δ = 62-4·2·48
Δ = -348
Delta is less than zero, so there is no solution for the equation
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