3(v-5)(-v+1)=0

Solution for 3(v-5)(-v+1)=0 equation:

3(v-5)(-v+1)=0

We add all the numbers together, and all the variables

3(v-5)(-1v+1)=0

We multiply parentheses ..

3(-1v^2+v+5v-5)=0

We multiply parentheses

-3v^2+3v+15v-15=0

We add all the numbers together, and all the variables

-3v^2+18v-15=0

a = -3; b = 18; c = -15;
Δ = b2-4ac
Δ = 182-4·(-3)·(-15)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-12}{2*-3}=\frac{-30}{-6}
=+5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+12}{2*-3}=\frac{-6}{-6}
=1
$