3(v-3)=9v+3-2(-3v-1)

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Solution for 3(v-3)=9v+3-2(-3v-1) equation: 



3(v-3)=9v+3-2(-3v-1)

We move all terms to the left:

3(v-3)-(9v+3-2(-3v-1))=0

We multiply parentheses

3v-(9v+3-2(-3v-1))-9=0



We calculate terms in parentheses: -(9v+3-2(-3v-1)), so:

9v+3-2(-3v-1)

determiningTheFunctionDomain
9v-2(-3v-1)+3

We multiply parentheses

9v+6v+2+3

We add all the numbers together, and all the variables

15v+5

Back to the equation:

-(15v+5)



We get rid of parentheses

3v-15v-5-9=0

We add all the numbers together, and all the variables

-12v-14=0

We move all terms containing v to the left, all other terms to the right

-12v=14

v=14/-12

v=-1+1/6

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