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(8x^2+17x)+6x^2=
We move all terms to the left:
(8x^2+17x)+6x^2-()=0
We add all the numbers together, and all the variables
6x^2+(8x^2+17x)=0
We get rid of parentheses
6x^2+8x^2+17x=0
We add all the numbers together, and all the variables
14x^2+17x=0
a = 14; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·14·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*14}=\frac{-34}{28} =-1+3/14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*14}=\frac{0}{28} =0 $
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