3(v-1)=v+4-2(-7v-1)

Solution for 3(v-1)=v+4-2(-7v-1) equation:

3(v-1)=v+4-2(-7v-1)

We move all terms to the left:

3(v-1)-(v+4-2(-7v-1))=0

We multiply parentheses

3v-(v+4-2(-7v-1))-3=0


We calculate terms in parentheses: -(v+4-2(-7v-1)), so:

v+4-2(-7v-1)

determiningTheFunctionDomain
v-2(-7v-1)+4

We multiply parentheses

v+14v+2+4

We add all the numbers together, and all the variables

15v+6

Back to the equation:

-(15v+6)


We get rid of parentheses

3v-15v-6-3=0

We add all the numbers together, and all the variables

-12v-9=0

We move all terms containing v to the left, all other terms to the right

-12v=9

v=9/-12

v=-3/4