3/y-3y+8=0

Solution for 3/y-3y+8=0 equation:

3/y-3y+8=0


Domain of the equation: y!=0

y∈R


We add all the numbers together, and all the variables

-3y+3/y+8=0

We multiply all the terms by the denominator


-3y*y+8*y+3=0

We add all the numbers together, and all the variables

8y-3y*y+3=0

Wy multiply elements

-3y^2+8y+3=0

a = -3; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·(-3)·3
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-10}{2*-3}=\frac{-18}{-6}
=+3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+10}{2*-3}=\frac{2}{-6}
=-1/3
$