3(v-1)=3v+1-2(-6v-7)

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Solution for 3(v-1)=3v+1-2(-6v-7) equation: 



3(v-1)=3v+1-2(-6v-7)

We move all terms to the left:

3(v-1)-(3v+1-2(-6v-7))=0

We multiply parentheses

3v-(3v+1-2(-6v-7))-3=0



We calculate terms in parentheses: -(3v+1-2(-6v-7)), so:

3v+1-2(-6v-7)

determiningTheFunctionDomain
3v-2(-6v-7)+1

We multiply parentheses

3v+12v+14+1

We add all the numbers together, and all the variables

15v+15

Back to the equation:

-(15v+15)



We get rid of parentheses

3v-15v-15-3=0

We add all the numbers together, and all the variables

-12v-18=0

We move all terms containing v to the left, all other terms to the right

-12v=18

v=18/-12

v=-1+1/2

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