-3(2w-3)+7w=5+2(5w-4)

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Solution for -3(2w-3)+7w=5+2(5w-4) equation: 



-3(2w-3)+7w=5+2(5w-4)

We move all terms to the left:

-3(2w-3)+7w-(5+2(5w-4))=0

We add all the numbers together, and all the variables

7w-3(2w-3)-(5+2(5w-4))=0

We multiply parentheses

7w-6w-(5+2(5w-4))+9=0



We calculate terms in parentheses: -(5+2(5w-4)), so:

5+2(5w-4)

determiningTheFunctionDomain
2(5w-4)+5

We multiply parentheses

10w-8+5

We add all the numbers together, and all the variables

10w-3

Back to the equation:

-(10w-3)



We add all the numbers together, and all the variables

w-(10w-3)+9=0

We get rid of parentheses

w-10w+3+9=0

We add all the numbers together, and all the variables

-9w+12=0

We move all terms containing w to the left, all other terms to the right

-9w=-12

w=-12/-9

w=1+1/3

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