3(u-5)-3=-2(-9u+8)-7u

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Solution for 3(u-5)-3=-2(-9u+8)-7u equation: 



3(u-5)-3=-2(-9u+8)-7u

We move all terms to the left:

3(u-5)-3-(-2(-9u+8)-7u)=0

We multiply parentheses

3u-(-2(-9u+8)-7u)-15-3=0



We calculate terms in parentheses: -(-2(-9u+8)-7u), so:

-2(-9u+8)-7u

We add all the numbers together, and all the variables

-7u-2(-9u+8)

We multiply parentheses

-7u+18u-16

We add all the numbers together, and all the variables

11u-16

Back to the equation:

-(11u-16)



We add all the numbers together, and all the variables

3u-(11u-16)-18=0

We get rid of parentheses

3u-11u+16-18=0

We add all the numbers together, and all the variables

-8u-2=0

We move all terms containing u to the left, all other terms to the right

-8u=2

u=2/-8

u=-1/4

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