3x+33=9(x+1)

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Solution for 3x+33=9(x+1) equation: 



3x+33=9(x+1)

We move all terms to the left:

3x+33-(9(x+1))=0



We calculate terms in parentheses: -(9(x+1)), so:

9(x+1)

We multiply parentheses

9x+9

Back to the equation:

-(9x+9)



We get rid of parentheses

3x-9x-9+33=0

We add all the numbers together, and all the variables

-6x+24=0

We move all terms containing x to the left, all other terms to the right

-6x=-24

x=-24/-6

x=+4

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