3(u-2)=5u+4-2(-3u-1)

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Solution for 3(u-2)=5u+4-2(-3u-1) equation: 



3(u-2)=5u+4-2(-3u-1)

We move all terms to the left:

3(u-2)-(5u+4-2(-3u-1))=0

We multiply parentheses

3u-(5u+4-2(-3u-1))-6=0



We calculate terms in parentheses: -(5u+4-2(-3u-1)), so:

5u+4-2(-3u-1)

determiningTheFunctionDomain
5u-2(-3u-1)+4

We multiply parentheses

5u+6u+2+4

We add all the numbers together, and all the variables

11u+6

Back to the equation:

-(11u+6)



We get rid of parentheses

3u-11u-6-6=0

We add all the numbers together, and all the variables

-8u-12=0

We move all terms containing u to the left, all other terms to the right

-8u=12

u=12/-8

u=-1+1/2

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