152=4(4r+6)

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Solution for 152=4(4r+6) equation: 



152=4(4r+6)

We move all terms to the left:

152-(4(4r+6))=0



We calculate terms in parentheses: -(4(4r+6)), so:

4(4r+6)

We multiply parentheses

16r+24

Back to the equation:

-(16r+24)



We get rid of parentheses

-16r-24+152=0

We add all the numbers together, and all the variables

-16r+128=0

We move all terms containing r to the left, all other terms to the right

-16r=-128

r=-128/-16

r=+8

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