3(u+9)=4u+12

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Solution for 3(u+9)=4u+12 equation: 



3(u+9)=4u+12

We move all terms to the left:

3(u+9)-(4u+12)=0

We multiply parentheses

3u-(4u+12)+27=0

We get rid of parentheses

3u-4u-12+27=0

We add all the numbers together, and all the variables

-1u+15=0

We move all terms containing u to the left, all other terms to the right

-u=-15

u=-15/-1

u=+15

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