3(u+2)+u=(4-1)+10

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Solution for 3(u+2)+u=(4-1)+10 equation: 



3(u+2)+u=(4-1)+10

We move all terms to the left:

3(u+2)+u-((4-1)+10)=0

We add all the numbers together, and all the variables

3(u+2)+u-(3+10)=0

We add all the numbers together, and all the variables

u+3(u+2)-13=0

We multiply parentheses

u+3u+6-13=0

We add all the numbers together, and all the variables

4u-7=0

We move all terms containing u to the left, all other terms to the right

4u=7

u=7/4

u=1+3/4

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