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5(2+x)-x=10+4(x+1x)
We move all terms to the left:
5(2+x)-x-(10+4(x+1x))=0
We add all the numbers together, and all the variables
5(x+2)-x-(10+4(+2x))=0
We add all the numbers together, and all the variables
-1x+5(x+2)-(10+4(+2x))=0
We multiply parentheses
-1x+5x-(10+4(+2x))+10=0
We calculate terms in parentheses: -(10+4(+2x)), so:We add all the numbers together, and all the variables
10+4(+2x)
determiningTheFunctionDomain 4(+2x)+10
We multiply parentheses
8x+10
Back to the equation:
-(8x+10)
4x-(8x+10)+10=0
We get rid of parentheses
4x-8x-10+10=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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