3(t-5)+7t=5(2t+4)-10

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Solution for 3(t-5)+7t=5(2t+4)-10 equation: 



3(t-5)+7t=5(2t+4)-10

We move all terms to the left:

3(t-5)+7t-(5(2t+4)-10)=0

We add all the numbers together, and all the variables

7t+3(t-5)-(5(2t+4)-10)=0

We multiply parentheses

7t+3t-(5(2t+4)-10)-15=0



We calculate terms in parentheses: -(5(2t+4)-10), so:

5(2t+4)-10

We multiply parentheses

10t+20-10

We add all the numbers together, and all the variables

10t+10

Back to the equation:

-(10t+10)



We add all the numbers together, and all the variables

10t-(10t+10)-15=0

We get rid of parentheses

10t-10t-10-15=0

We add all the numbers together, and all the variables

-25!=0

There is no solution for this equation

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