(5y+10)/4=(6y+3)/3

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Solution for (5y+10)/4=(6y+3)/3 equation: 



(5y+10)/4=(6y+3)/3

We move all terms to the left:

(5y+10)/4-((6y+3)/3)=0

We calculate fractions


5y/()+(-((6y+3)*4)/()=0



We calculate terms in parentheses: +(-((6y+3)*4)/(), so:

-((6y+3)*4)/(

We multiply all the terms by the denominator


-((6y+3)*4)



We calculate terms in parentheses: -((6y+3)*4), so:

(6y+3)*4

We multiply parentheses

24y+12

Back to the equation:

-(24y+12)



We get rid of parentheses

-24y-12

Back to the equation:

+(-24y-12)



We get rid of parentheses

5y/()-24y-12=0

We multiply all the terms by the denominator


5y-24y*()-12*()=0

We add all the numbers together, and all the variables

5y-24y*()=0

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