3(t-2)+7t=104

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Solution for 3(t-2)+7t=104 equation: 



3(t-2)+7t=104

We move all terms to the left:

3(t-2)+7t-(104)=0

We add all the numbers together, and all the variables

7t+3(t-2)-104=0

We multiply parentheses

7t+3t-6-104=0

We add all the numbers together, and all the variables

10t-110=0

We move all terms containing t to the left, all other terms to the right

10t=110

t=110/10

t=11

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