3(t-1)-2(2t-3)=5(t+3)

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Solution for 3(t-1)-2(2t-3)=5(t+3) equation: 



3(t-1)-2(2t-3)=5(t+3)

We move all terms to the left:

3(t-1)-2(2t-3)-(5(t+3))=0

We multiply parentheses

3t-4t-(5(t+3))-3+6=0



We calculate terms in parentheses: -(5(t+3)), so:

5(t+3)

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)



We add all the numbers together, and all the variables

-1t-(5t+15)+3=0

We get rid of parentheses

-1t-5t-15+3=0

We add all the numbers together, and all the variables

-6t-12=0

We move all terms containing t to the left, all other terms to the right

-6t=12

t=12/-6

t=-2

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