(X+3)(y-3)-y(y+5)=6

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Solution for (X+3)(y-3)-y(y+5)=6 equation: 



(X+3)(X-3)-X(X+5)=6

We move all terms to the left:

(X+3)(X-3)-X(X+5)-(6)=0

We use the square of the difference formula

X^2-X(X+5)-9-6=0

We multiply parentheses

X^2-X^2-5X-9-6=0

We add all the numbers together, and all the variables

-5X-15=0

We move all terms containing X to the left, all other terms to the right

-5X=15

X=15/-5

X=-3

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