3(t-1)-2(2t+3)=(t+3)

Solution for 3(t-1)-2(2t+3)=(t+3) equation:

3(t-1)-2(2t+3)=(t+3)

We move all terms to the left:

3(t-1)-2(2t+3)-((t+3))=0

We multiply parentheses

3t-4t-((t+3))-3-6=0


We calculate terms in parentheses: -((t+3)), so:

(t+3)

We get rid of parentheses

t+3

Back to the equation:

-(t+3)


We add all the numbers together, and all the variables

-1t-(t+3)-9=0

We get rid of parentheses

-1t-t-3-9=0

We add all the numbers together, and all the variables

-2t-12=0

We move all terms containing t to the left, all other terms to the right

-2t=12

t=12/-2

t=-6