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(x+3)/(2x-1)=52/39
We move all terms to the left:
(x+3)/(2x-1)-(52/39)=0
Domain of the equation: (2x-1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=1
x!=1/2
x!=1/2
x∈R
(x+3)/(2x-1)-(+52/39)=0
We get rid of parentheses
(x+3)/(2x-1)-52/39=0
We calculate fractions
(39x+117)/(78x-39)+(-104x+52)/(78x-39)=0
We multiply all the terms by the denominator
(39x+117)+(-104x+52)=0
We get rid of parentheses
39x-104x+117+52=0
We add all the numbers together, and all the variables
-65x+169=0
We move all terms containing x to the left, all other terms to the right
-65x=-169
x=-169/-65
x=2+3/5
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