3(t+7)+4(t+5)=7t+41

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Solution for 3(t+7)+4(t+5)=7t+41 equation: 



3(t+7)+4(t+5)=7t+41

We move all terms to the left:

3(t+7)+4(t+5)-(7t+41)=0

We multiply parentheses

3t+4t-(7t+41)+21+20=0

We get rid of parentheses

3t+4t-7t-41+21+20=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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