3(t+2)=2(t+1)

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Solution for 3(t+2)=2(t+1) equation: 



3(t+2)=2(t+1)

We move all terms to the left:

3(t+2)-(2(t+1))=0

We multiply parentheses

3t-(2(t+1))+6=0



We calculate terms in parentheses: -(2(t+1)), so:

2(t+1)

We multiply parentheses

2t+2

Back to the equation:

-(2t+2)



We get rid of parentheses

3t-2t-2+6=0

We add all the numbers together, and all the variables

t+4=0

We move all terms containing t to the left, all other terms to the right

t=-4

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