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-80/x=-40x
We move all terms to the left:
-80/x-(-40x)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
-80/x+40x=0
We multiply all the terms by the denominator
40x*x-80=0
Wy multiply elements
40x^2-80=0
a = 40; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·40·(-80)
Δ = 12800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12800}=\sqrt{6400*2}=\sqrt{6400}*\sqrt{2}=80\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{2}}{2*40}=\frac{0-80\sqrt{2}}{80} =-\frac{80\sqrt{2}}{80} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{2}}{2*40}=\frac{0+80\sqrt{2}}{80} =\frac{80\sqrt{2}}{80} =\sqrt{2} $
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