3(t+2)=(2+3t)+6

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Solution for 3(t+2)=(2+3t)+6 equation: 



3(t+2)=(2+3t)+6

We move all terms to the left:

3(t+2)-((2+3t)+6)=0

We add all the numbers together, and all the variables

3(t+2)-((3t+2)+6)=0

We multiply parentheses

3t-((3t+2)+6)+6=0



We calculate terms in parentheses: -((3t+2)+6), so:

(3t+2)+6

We get rid of parentheses

3t+2+6

We add all the numbers together, and all the variables

3t+8

Back to the equation:

-(3t+8)



We get rid of parentheses

3t-3t-8+6=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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