(n*n)+12n=28

Solution for (n*n)+12n=28 equation:

(n*n)+12n=28

We move all terms to the left:

(n*n)+12n-(28)=0

We add all the numbers together, and all the variables

(+n*n)+12n-28=0

We add all the numbers together, and all the variables

12n+(+n*n)-28=0

We get rid of parentheses

12n+n*n-28=0

Wy multiply elements

n^2+12n-28=0

a = 1; b = 12; c = -28;
Δ = b2-4ac
Δ = 122-4·1·(-28)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-16}{2*1}=\frac{-28}{2}
=-14
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+16}{2*1}=\frac{4}{2}
=2
$