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2k-(2/3)=3k-(9/2)
We move all terms to the left:
2k-(2/3)-(3k-(9/2))=0
We add all the numbers together, and all the variables
2k-(3k-(+9/2))-(+2/3)=0
We get rid of parentheses
2k-(3k-(+9/2))-2/3=0
We calculate fractions
2k+(-(3k-(+9*3)/()+()/()=0
We calculate terms in parentheses: +(-(3k-(+9*3)/()+()/(), so:
-(3k-(+9*3)/()+()/(
We can not solve this equation
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