(2/3)(3k-1)=(3/2)(2k-3)

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Solution for (2/3)(3k-1)=(3/2)(2k-3) equation: 



(2/3)(3k-1)=(3/2)(2k-3)

We move all terms to the left:

(2/3)(3k-1)-((3/2)(2k-3))=0



Domain of the equation: 3)(3k-1)!=0

k∈R





Domain of the equation: 2)(2k-3))!=0

k∈R



We add all the numbers together, and all the variables

(+2/3)(3k-1)-((+3/2)(2k-3))=0

We multiply parentheses ..

(+6k^2+2/3*-1)-((+3/2)(2k-3))=0

We calculate fractions


((+6k^2+2*2)(2k-3)))/(-1)*2)(2k-3))+3*)+()/(-1)*2)(2k-3))+3*)=0

We calculate fractions


(((+6k^2+2*2)(2k-3)))*(-1)*2)(2k-3))+3*))/((*(-1)*2)2k)+(-1)*2)(2k-3))+3*)+()*()/((*(-1)*2)2k)=0

We can not solve this equation

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