3(t+2)-13t=7(t-4)

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Solution for 3(t+2)-13t=7(t-4) equation: 



3(t+2)-13t=7(t-4)

We move all terms to the left:

3(t+2)-13t-(7(t-4))=0

We add all the numbers together, and all the variables

-13t+3(t+2)-(7(t-4))=0

We multiply parentheses

-13t+3t-(7(t-4))+6=0



We calculate terms in parentheses: -(7(t-4)), so:

7(t-4)

We multiply parentheses

7t-28

Back to the equation:

-(7t-28)



We add all the numbers together, and all the variables

-10t-(7t-28)+6=0

We get rid of parentheses

-10t-7t+28+6=0

We add all the numbers together, and all the variables

-17t+34=0

We move all terms containing t to the left, all other terms to the right

-17t=-34

t=-34/-17

t=+2

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