3(q+1)=9(q+1)

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Solution for 3(q+1)=9(q+1) equation: 



3(q+1)=9(q+1)

We move all terms to the left:

3(q+1)-(9(q+1))=0

We multiply parentheses

3q-(9(q+1))+3=0



We calculate terms in parentheses: -(9(q+1)), so:

9(q+1)

We multiply parentheses

9q+9

Back to the equation:

-(9q+9)



We get rid of parentheses

3q-9q-9+3=0

We add all the numbers together, and all the variables

-6q-6=0

We move all terms containing q to the left, all other terms to the right

-6q=6

q=6/-6

q=-1

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