3(s-14)+7(s-12)=14

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Solution for 3(s-14)+7(s-12)=14 equation: 



3(s-14)+7(s-12)=14

We move all terms to the left:

3(s-14)+7(s-12)-(14)=0

We multiply parentheses

3s+7s-42-84-14=0

We add all the numbers together, and all the variables

10s-140=0

We move all terms containing s to the left, all other terms to the right

10s=140

s=140/10

s=14

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