3(q-10)+4(q-19)=13

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Solution for 3(q-10)+4(q-19)=13 equation:


Simplifying
3(q + -10) + 4(q + -19) = 13

Reorder the terms:
3(-10 + q) + 4(q + -19) = 13
(-10 * 3 + q * 3) + 4(q + -19) = 13
(-30 + 3q) + 4(q + -19) = 13

Reorder the terms:
-30 + 3q + 4(-19 + q) = 13
-30 + 3q + (-19 * 4 + q * 4) = 13
-30 + 3q + (-76 + 4q) = 13

Reorder the terms:
-30 + -76 + 3q + 4q = 13

Combine like terms: -30 + -76 = -106
-106 + 3q + 4q = 13

Combine like terms: 3q + 4q = 7q
-106 + 7q = 13

Solving
-106 + 7q = 13

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '106' to each side of the equation.
-106 + 106 + 7q = 13 + 106

Combine like terms: -106 + 106 = 0
0 + 7q = 13 + 106
7q = 13 + 106

Combine like terms: 13 + 106 = 119
7q = 119

Divide each side by '7'.
q = 17

Simplifying
q = 17

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