5(2x-1)-3(x-4)=7(x+1)

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Solution for 5(2x-1)-3(x-4)=7(x+1) equation:


Simplifying
5(2x + -1) + -3(x + -4) = 7(x + 1)

Reorder the terms:
5(-1 + 2x) + -3(x + -4) = 7(x + 1)
(-1 * 5 + 2x * 5) + -3(x + -4) = 7(x + 1)
(-5 + 10x) + -3(x + -4) = 7(x + 1)

Reorder the terms:
-5 + 10x + -3(-4 + x) = 7(x + 1)
-5 + 10x + (-4 * -3 + x * -3) = 7(x + 1)
-5 + 10x + (12 + -3x) = 7(x + 1)

Reorder the terms:
-5 + 12 + 10x + -3x = 7(x + 1)

Combine like terms: -5 + 12 = 7
7 + 10x + -3x = 7(x + 1)

Combine like terms: 10x + -3x = 7x
7 + 7x = 7(x + 1)

Reorder the terms:
7 + 7x = 7(1 + x)
7 + 7x = (1 * 7 + x * 7)
7 + 7x = (7 + 7x)

Add '-7' to each side of the equation.
7 + -7 + 7x = 7 + -7 + 7x

Combine like terms: 7 + -7 = 0
0 + 7x = 7 + -7 + 7x
7x = 7 + -7 + 7x

Combine like terms: 7 + -7 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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