3(q+1)=2(q-1)

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Solution for 3(q+1)=2(q-1) equation: 



3(q+1)=2(q-1)

We move all terms to the left:

3(q+1)-(2(q-1))=0

We multiply parentheses

3q-(2(q-1))+3=0



We calculate terms in parentheses: -(2(q-1)), so:

2(q-1)

We multiply parentheses

2q-2

Back to the equation:

-(2q-2)



We get rid of parentheses

3q-2q+2+3=0

We add all the numbers together, and all the variables

q+5=0

We move all terms containing q to the left, all other terms to the right

q=-5

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