1/5(a+9)=1/2(7-a)

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Solution for 1/5(a+9)=1/2(7-a) equation: 



1/5(a+9)=1/2(7-a)

We move all terms to the left:

1/5(a+9)-(1/2(7-a))=0



Domain of the equation: 5(a+9)!=0

a∈R





Domain of the equation: 2(7-a))!=0

a∈R



We add all the numbers together, and all the variables

1/5(a+9)-(1/2(-1a+7))=0

We calculate fractions


(2a(-)/(5(a+9)*2(-1a+7)))+(-5aa/(5(a+9)*2(-1a+7)))=0



We calculate terms in parentheses: +(2a(-)/(5(a+9)*2(-1a+7))), so:

2a(-)/(5(a+9)*2(-1a+7))

We add all the numbers together, and all the variables

2a0/(5(a+9)*2(-1a+7))

We multiply all the terms by the denominator


2a0

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)





We calculate terms in parentheses: +(-5aa/(5(a+9)*2(-1a+7))), so:

-5aa/(5(a+9)*2(-1a+7))

We multiply all the terms by the denominator


-5aa

Back to the equation:

+(-5aa)



We get rid of parentheses

2a-5aa=0

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