3(p-3)+1=8-(p-4)

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Solution for 3(p-3)+1=8-(p-4) equation: 



3(p-3)+1=8-(p-4)

We move all terms to the left:

3(p-3)+1-(8-(p-4))=0

We multiply parentheses

3p-(8-(p-4))-9+1=0



We calculate terms in parentheses: -(8-(p-4)), so:

8-(p-4)

determiningTheFunctionDomain
-(p-4)+8

We get rid of parentheses

-p+4+8

We add all the numbers together, and all the variables

-1p+12

Back to the equation:

-(-1p+12)



We add all the numbers together, and all the variables

3p-(-1p+12)-8=0

We get rid of parentheses

3p+1p-12-8=0

We add all the numbers together, and all the variables

4p-20=0

We move all terms containing p to the left, all other terms to the right

4p=20

p=20/4

p=5

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