(7t-2)+(-3t+1)=3(1-3t)

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Solution for (7t-2)+(-3t+1)=3(1-3t) equation: 



(7t-2)+(-3t+1)=3(1-3t)

We move all terms to the left:

(7t-2)+(-3t+1)-(3(1-3t))=0

We add all the numbers together, and all the variables

(7t-2)+(-3t+1)-(3(-3t+1))=0

We get rid of parentheses

7t-3t-(3(-3t+1))-2+1=0



We calculate terms in parentheses: -(3(-3t+1)), so:

3(-3t+1)

We multiply parentheses

-9t+3

Back to the equation:

-(-9t+3)



We add all the numbers together, and all the variables

4t-(-9t+3)-1=0

We get rid of parentheses

4t+9t-3-1=0

We add all the numbers together, and all the variables

13t-4=0

We move all terms containing t to the left, all other terms to the right

13t=4

t=4/13

t=4/13

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