3(p-1)=6(p-8)-12

Solution for 3(p-1)=6(p-8)-12 equation:

3(p-1)=6(p-8)-12

We move all terms to the left:

3(p-1)-(6(p-8)-12)=0

We multiply parentheses

3p-(6(p-8)-12)-3=0


We calculate terms in parentheses: -(6(p-8)-12), so:

6(p-8)-12

We multiply parentheses

6p-48-12

We add all the numbers together, and all the variables

6p-60

Back to the equation:

-(6p-60)


We get rid of parentheses

3p-6p+60-3=0

We add all the numbers together, and all the variables

-3p+57=0

We move all terms containing p to the left, all other terms to the right

-3p=-57

p=-57/-3

p=+19