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2(x-(2x+12)+11)=2(x+1)
We move all terms to the left:
2(x-(2x+12)+11)-(2(x+1))=0
We calculate terms in parentheses: -(2(x+1)), so:We get rid of parentheses
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
2(x-(2x+12)+11)-2x-2=0
We add all the numbers together, and all the variables
-2x+2(x-(2x+12)+11)-2=0
We move all terms containing x to the left, all other terms to the right
-2x+2(x-(2x+12)+11)=2
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