3(p+2)-4(2p+3)=6-3(p+1)

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Solution for 3(p+2)-4(2p+3)=6-3(p+1) equation: 



3(p+2)-4(2p+3)=6-3(p+1)

We move all terms to the left:

3(p+2)-4(2p+3)-(6-3(p+1))=0

We multiply parentheses

3p-8p-(6-3(p+1))+6-12=0



We calculate terms in parentheses: -(6-3(p+1)), so:

6-3(p+1)

determiningTheFunctionDomain
-3(p+1)+6

We multiply parentheses

-3p-3+6

We add all the numbers together, and all the variables

-3p+3

Back to the equation:

-(-3p+3)



We add all the numbers together, and all the variables

-5p-(-3p+3)-6=0

We get rid of parentheses

-5p+3p-3-6=0

We add all the numbers together, and all the variables

-2p-9=0

We move all terms containing p to the left, all other terms to the right

-2p=9

p=9/-2

p=-4+1/2

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