2t-6(2t-2(t+3))+5=8+t

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Solution for 2t-6(2t-2(t+3))+5=8+t equation: 



2t-6(2t-2(t+3))+5=8+t

We move all terms to the left:

2t-6(2t-2(t+3))+5-(8+t)=0

We add all the numbers together, and all the variables

2t-6(2t-2(t+3))-(t+8)+5=0

We get rid of parentheses

2t-6(2t-2(t+3))-t-8+5=0

We add all the numbers together, and all the variables

t-6(2t-2(t+3))-3=0

We move all terms containing t to the left, all other terms to the right

t-6(2t-2(t+3))=3

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